Friday, October 16, 2015

A Combinatoric Combinator

I wrote this while I was playing around with using q on a hobby project, and I thought I’d share it in case anyone else might find it useful.
It takes a number k, a function f, and a list or dictionary y of count n, and runs f once for each of the k-combinations of y. The result is returned as a dictionary with the function outputs as its values and its keys determined by the type of y: if y is a list, its keys are the subsets of y that produced the outputs; if y is a dictionary, its keys are the subsets of the keys of y that index the subsets of y that produced the outputs.

eachc:{
    c:(where reverse 0b vs)each c@:where((first x)=sum 0b vs)each c:til"j"$2 xexp count y;
    (last x)peach$[99h=type y;(key each y)!y:y{((key x)y)#x}/:c;y!y:y@/:c]}

Examples:
q)eachc[(3;sum)]til 5
0 1 2| 3
0 1 3| 4
0 2 3| 5
1 2 3| 6
0 1 4| 5
0 2 4| 6
1 2 4| 7
0 3 4| 7
1 3 4| 8
2 3 4| 9
q)eachc[(3;sum)]`a`b`c`d`e!til 5
a b c| 3
a b d| 4
a c d| 5
b c d| 6
a b e| 5
a c e| 6
b c e| 7
a d e| 7
b d e| 8
c d e| 9
q)
Notes and caveats:
On little-endian machines (i.e. Sparc), the reverse will probably need to be removed.
The size of the result set gets very big very quickly—an n of thirty is probably infeasible for most machines.
I’ve written it to execute f on the combinations with peach, rather than each; this may or may not be appropriate, depending on the nature of any given f and y.

Labels:

2 Comments:

At October 2, 2017 at 9:50 AM , Blogger australia resume writing service said...

Thanks for this informative post, the lack of background data and basic knowledge makes this post a little hard to understand however I'm sure those with knowledge of this understand the post better.

 
At October 27, 2017 at 3:12 PM , Blogger Siegfried Emmelmann said...


Hi, I read your blogs like every week. Your humoristic style is awesome, keep it up! capital one login

 

Post a Comment

Subscribe to Post Comments [Atom]

<< Home